Which two solutions form the high molecular weight complex in Gram's staining?

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Multiple Choice

Which two solutions form the high molecular weight complex in Gram's staining?

Explanation:
In Gram staining, the high molecular weight complex is created when the primary stain (crystal violet) interacts with the mordant (Gram’s iodine). The iodine binds to crystal violet and forms a CV–I complex that is large and becomes trapped inside the thick peptidoglycan layer of Gram-positive cells. This complex withstands the decolorization step, so those cells stay purple, while Gram-negative cells lose the dye and take up the counterstain. The other pairings don’t form that retained complex: the counterstain (safranin) is used after decolorization, not to build the large dye–mordant complex; methylene blue isn’t involved in forming the CV–I complex in Gram staining.

In Gram staining, the high molecular weight complex is created when the primary stain (crystal violet) interacts with the mordant (Gram’s iodine). The iodine binds to crystal violet and forms a CV–I complex that is large and becomes trapped inside the thick peptidoglycan layer of Gram-positive cells. This complex withstands the decolorization step, so those cells stay purple, while Gram-negative cells lose the dye and take up the counterstain.

The other pairings don’t form that retained complex: the counterstain (safranin) is used after decolorization, not to build the large dye–mordant complex; methylene blue isn’t involved in forming the CV–I complex in Gram staining.

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